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Oracle 1Z0-829 (Java SE 17 Developer) Exam is a certification program offered by Oracle Corporation for individuals who want to demonstrate their skills and knowledge in Java SE 17 development. Java SE 17 Developer certification exam is designed to test the candidate's ability to design and develop Java applications using the latest features and enhancements introduced in Java SE 17. It covers a wide range of topics including Java language enhancements, new APIs, modular programming, security, and performance improvements.
NEW QUESTION # 29
Given:
What is the result?
- A. runsruns
- B. flipsflips
- C. runsflips
- D. flipsruns
- E. Compilation fails
Answer: E
Explanation:
The code fragment will fail to compile because the play method in the Dog class is declared as private, which means that it cannot be accessed from outside the class. The main method is trying to call the play method on a Dog object, which is not allowed. Therefore, the code fragment will produce a compilation error.
NEW QUESTION # 30
Given:
Which two modifications enable the code to print Open Close?
- A.
- B.
- C.
- D.
- E.
Answer: C,D
Explanation:
Explanation
The code given is a try-with-resources statement that declares a resource of type AutoCloseable. The resource is an anonymous class that implements the AutoCloseable interface and overrides the close() method. The code also has a print() method that prints the value of the variable s. The code is supposed to print "Open Close", but it does not compile because of two errors.
The first error is at line n1, where the anonymous class is missing a semicolon at the end of its declaration.
This causes a syntax error and prevents the code from compiling. To fix this error, option B adds a semicolon after the closing curly brace of the anonymous class.
The second error is at line n2, where the print() method is called without an object reference. This causes a compilation error because the print() method is not static and cannot be invoked without an object. To fix this error, option E adds an object reference to the print() method by using the variable t.
Therefore, options B and E are correct and enable the code to print "Open Close".
NEW QUESTION # 31
Given the code fragment:
What is the result?
- A. 1
1
1 - B. 1
2
-4 - C. 0
- D. 1
- E. 2
2
0 - F. 2
Answer: C
Explanation:
Explanation
The code fragment uses the Collections.binarySearch method to search for the string "e3" in the list. The first search returns the index of the element, which is 2. The second search returns the index of the element, which is 0. The third search returns the index of the element, which is -4. The final result is
2. References: Collections (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 32
Given the course table:
Given the code fragment:
- A. 0
- B. true
- C. 1
- D. false
Answer: B
Explanation:
The code fragment will execute the update statement and set the course fee of the course with ID 1021 to 5000. The executeUpdate method returns an int value that indicates the number of rows affected by the SQL statement. In this case, only one row will be updated, so the result variable will be 1. The if statement will check if the result is greater than 0, which is true, and print "Updated successfully". Therefore, the output of the code fragment is true. Reference: https://education.oracle.com/products/trackp_OCPJSE17, https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487, https://docs.oracle.com/en/java/javase/17/docs/api/java.sql/java/sql/Statement.html#executeUpdate(java.lang.String)
NEW QUESTION # 33
Given:
What is the result?
- A. runsruns
- B. flipsflips
- C. runsflips
- D. flipsruns
- E. Compilation fails
Answer: E
Explanation:
Explanation
The code fragment will fail to compile because the play method in the Dog class is declared as private, which means that it cannot be accessed from outside the class. The main method is trying to call the play method on a Dog object, which is not allowed. Therefore, the code fragment will produce a compilation error.
NEW QUESTION # 34
Given:
What is the result?
- A. 1001
100
1000 - B. 101
101
1000 - C. 100
100
1000 - D. 1001
1001
1000
Answer: A
Explanation:
Explanation
The code fragment is using the bitwise operators & (AND), | (OR), and ^ (XOR) to perform operations on the binary representations of the integer values. The & operator returns a 1 in each bit position where both operands have a 1, the | operator returns a 1 in each bit position where either operand has a 1, and the ^ operator returns a 1 in each bit position where only one operand has a 1. The binary representations of the integer values are as follows:
1000 = 1111101000
100 = 1100100
101 = 1100101
The code fragment performs the following operations:
x = x ^ y; // x becomes 1111010101, which is 1001 in decimal
y = x ^ y; // y becomes 1100100, which is 100 in decimal
x = x ^ y; // x becomes 1100101, which is 101 in decimal
The code fragment then prints out the values of x, y, and z, which are 1001, 100, and 1000 respectively.
Therefore, option D is correct.
NEW QUESTION # 35
Given the code fragment:
Which action sorts the book list?
- A. At Line n2, replace compareTo () with compare ().
- B. At Line n2, replace books,sort() with books.stream().sort(0.
- C. At Line n1, convert type to mutable array type.
- D. At line n1, convert books type to mutable ArrayList type.
Answer: A
Explanation:
The code fragment is trying to sort a list of books using the Collections.sort() method. The correct answer is D, because the compareTo() method is not the correct way to compare two objects in a Comparator. The compare() method is the correct way to compare two objects in a Comparator and return an int value that indicates their order1. The compareTo() method is used to implement the Comparable interface, which defines the natural order of objects of a class2. The other options are incorrect because they either do not change the type of the list, which is already mutable, or they do not use the correct syntax for sorting a stream, which requires a terminal operation such as collect()3. Reference: Comparator (Java SE 17 & JDK 17), Comparable (Java SE 17 & JDK 17), Stream (Java SE 17 & JDK 17)
NEW QUESTION # 36
Given:
Which action enables the code to compile?
- A. Replace 15 with item.display (''Flower'');
- B. Replace 7 with public void display (string design) {
- C. Replace 3 with private static void display () {
- D. Replace 2 with static string name;
Answer: B
Explanation:
Explanation
The answer is C because the code fragment contains a syntax error in line 7, where the method display is declared without any parameter type. This causes a compilation error, as Java requires the parameter type to be specified for each method parameter. To fix this error, the parameter type should be added before the parameter name, such as string design. This will enable the code to compile and run without any errors.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Methods
NEW QUESTION # 37
Given the code fragment:
Which code fragment invokes all callable objects in the workers set?
- A.
- B.
- C.
- D.
Answer: D
Explanation:
Explanation
The code fragment in Option C invokes all callable objects in the workers set by using the ExecutorService's invokeAll() method. This method takes a collection of Callable objects and returns a list of Future objects representing the results of the tasks. The other options are incorrect because they either use the wrong method (invokeAny() or submit()) or have syntax errors (missing parentheses or semicolons). References: AbstractExecutorService (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 38
Given the code fragment:
What is the result?
- A. A compilation error occurs at Line n1.
- B. Logged out at: 2021-0112T21:58:19.880z
- C. Logged out at: 2021-01-12T21:58:00z
- D. Can't logout
Answer: C
Explanation:
Explanation
The code fragment is using the Java SE 17 API to get the current time and then truncating it to minutes. The result will be the current time truncated to minutes, which is why option B is correct. References:
https://education.oracle.com/products/trackp_OCPJSE17
https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487
https://docs.oracle.com/javase/17/docs/api/java.base/java/time/Instant.html#truncatedTo(java.time.tempora
NEW QUESTION # 39
Given the code fragment:
Which code fragment invokes all callable objects in the workers set?
- A.
- B.
- C.
- D.
Answer: C
Explanation:
The code fragment in Option C invokes all callable objects in the workers set by using the ExecutorService's invokeAll() method. This method takes a collection of Callable objects and returns a list of Future objects representing the results of the tasks. The other options are incorrect because they either use the wrong method (invokeAny() or submit()) or have syntax errors (missing parentheses or semicolons). Reference: AbstractExecutorService (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 40
Which statement is true about modules?
- A. Only named modules are on the module path.
- B. Only automatic modules are on the module path.
- C. Automatic and named modules are on the module path.
- D. Automatic and unnamed modules are on the module path.
- E. Only unnamed modules are on the module path.
Answer: C
Explanation:
Explanation
A module path is a sequence of directories that contain modules or JAR files. A named module is a module that has a name and a module descriptor (module-info.class) that declares its dependencies and exports. An automatic module is a module that does not have a module descriptor, but is derived from the name and contents of a JAR file. Both named and automatic modules can be placed on the module path, and they can be resolved by the Java runtime. An unnamed module is a special module that contains all the classes that are not in any other module, such as those on the class path. An unnamed module is not on the module path, but it can read all other modules.
NEW QUESTION # 41
Given:
Which statement is true?
- A. The program throws ClassCastException
- B. The program throws StockException.
- C. The program throws outofStockException.
- D. The program fails to compile.
Answer: D
Explanation:
Explanation
The answer is B because the code fragment contains a syntax error that prevents it from compiling. The code fragment tries to catch a StockException in line 10, but the catch block does not have a parameter of type StockException. The catch block should have a parameter of type StockException, such as:
catch (StockException e) { // handle the exception }
This is required by the Java syntax for the catch clause, which must have a parameter that is a subclass of Throwable. Without a parameter, the catch block is invalid and causes a compilation error.
Option A is incorrect because the program does not throw a StockException, as it does not compile.
Option C is incorrect because the program does not throw an OutofStockException, as it does not compile.
Option D is incorrect because the program does not throw a ClassCastException, as it does not compile.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
The try-with-resources Statement (The Java™ Tutorials > Essential Classes > Exceptions) The catch Blocks (The Java™ Tutorials > Essential Classes > Exceptions)
NEW QUESTION # 42
Given:
Which statement is true while the program prints GC?
- A. Both the objects previously referenced by t1 are eligible for garbage collection.
- B. None of the objects are eligible for garbage collection.
- C. Only one of the objects previously referenced by t1 is eligible for garbage collection.
- D. Only the object referenced by t2 is eligible for garbage collection.
Answer: A
NEW QUESTION # 43
Given:
- A. Hello
- B. there
- C. A NumberFormatException is thrown
- D. Compilation fails
Answer: D
Explanation:
The code fragment will fail to compile because the parseInt method of the Integer class is a static method, which means that it can be invoked without creating an object of the class. However, the code is trying to invoke the parseInt method on an object of type Integer, which is not allowed. The correct way to invoke the parseInt method is by using the class name, such as Integer.parseInt (s). Therefore, the code fragment will produce a compilation error. Reference: Integer (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 44
Given the code fragment:
Which code line n1, obtains the java.io.Console object?
- A.
- B.
- C.
- D.
- E.
Answer: C
Explanation:
The code fragment is trying to obtain the java.io.Console object, which is a class that provides methods to access the character-based console device, if any, associated with the current Java virtual machine. The correct way to obtain the Console object is to call the static method Console console() in the java.lang.System class. This method returns the unique Console object associated with the current Java virtual machine, if any. Therefore, option A is correct, as it calls System.console() and assigns it to a Console variable. Reference:
https://docs.oracle.com/javase/17/docs/api/java.base/java/io/Console.html
https://docs.oracle.com/javase/17/docs/api/java.base/java/lang/System.html#console()
https://education.oracle.com/products/trackp_OCPJSE17
https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487
NEW QUESTION # 45
Given:
Which two method invocation execute?
- A. IFace.m2();
- B. new MyC() .m2 ();
- C. IFace myclassobj = new Myc (); myclassObj.m3 ();
- D. Ifnce.m3 ();
- E. IFace .,4():
- F. iFace mucloassObj = new Myc (); myClassObj.m4();
Answer: B,E
Explanation:
Explanation
The code given is an interface and a class that implements the interface. The interface has three methods, m1(), m2(), and m3(). The class has one method, m1(). The only two method invocations that will execute are D and E.
D is a call to the m2() method in the class, and E is a call to the m3() method in the interface. References:
https://education.oracle.com/products/trackp_OCPJSE17, 3, 4, 5
NEW QUESTION # 46
Assuming that the data, txt file exists and has the following content:
Text1
Text2
Text3
Given the code fragment:
What is the result?
- A. text1-text2-text3
text3 - B. text1-text2-text3
A java.lang.indexoutofBoundsException is thrown. - C. text1-
text2-
text3-
text3 - D. text1-text2-text3
text1
text2
text3
Answer: A
Explanation:
The answer is D because the code fragment reads the file "data.txt" and collects all the lines in the file into a single string, separated by hyphens. Then, it prints the resulting string. Next, it attempts to read the fourth line in the file (index 3) and print it. However, since the file only has three lines, an IndexOutOfBoundsException is thrown. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Read contents of a file using Files class in Java
NEW QUESTION # 47
Assume you have an automatic module from the module path display-ascii-0.2. jar. Which name is given to the automatic module based on the given JAR file?
- A. Display-ascii
- B. Display-ascii-0.2
- C. Display.ascii
- D. Display-ascii-0
Answer: A
Explanation:
An automatic module name is derived from the name of the JAR file when it does not contain a module-info.class file. If the JAR file has an "Automatic-Module-Name" attribute in its main manifest, then its value is the module name. Otherwise, the module name is derived from the JAR file's name by removing any version numbers and converting it to lower case. Therefore, for a JAR named display-ascii-0.2.jar, the automatic module name would be display-ascii, following these rules.
NEW QUESTION # 48
Given:
What is the result?
- A. 1001
100
1000 - B. 101
101
1000 - C. 100
100
1000 - D. 1001
1001
1000
Answer: A
Explanation:
The code fragment is using the bitwise operators & (AND), | (OR), and ^ (XOR) to perform operations on the binary representations of the integer values. The & operator returns a 1 in each bit position where both operands have a 1, the | operator returns a 1 in each bit position where either operand has a 1, and the ^ operator returns a 1 in each bit position where only one operand has a 1. The binary representations of the integer values are as follows:
1000 = 1111101000
100 = 1100100
101 = 1100101
The code fragment performs the following operations:
x = x ^ y; // x becomes 1111010101, which is 1001 in decimal
y = x ^ y; // y becomes 1100100, which is 100 in decimal
x = x ^ y; // x becomes 1100101, which is 101 in decimal
The code fragment then prints out the values of x, y, and z, which are 1001, 100, and 1000 respectively. Therefore, option D is correct.
NEW QUESTION # 49
Which two code fragments compile?
- A.
- B.
- C.
- D.
- E.
Answer: A,B
Explanation:
The two code fragments that compile are B and E. These are the only ones that use the correct syntax for declaring and initializing a var variable. The var keyword is a reserved type name that allows the compiler to infer the type of the variable based on the initializer expression. However, the var variable must have an initializer, and the initializer must not be null or a lambda expression. Therefore, option A is invalid because it does not have an initializer, option C is invalid because it has a null initializer, and option D is invalid because it has a lambda expression as an initializer. Option B is valid because it has a String initializer, and option E is valid because it has an int initializer.
https://docs.oracle.com/en/java/javase/17/language/local-variable-type-inference.html
NEW QUESTION # 50
Given:
What is the result?
- A. Compilation fails.
- B. (Bicycle, car, motorcycle, truck)
- C. (3:bicycle, 0:car, 0motercycle, 5:truck)
- D. Bicycle =7, car=7, motorcycle=7, truck=7)
- E. Bicycle-1, car=3, motorcycle=1, truck=2)
Answer: A
Explanation:
Explanation
The answer is E because the code fragment contains several syntax errors that prevent it from compiling.
Some of the errors are:
The enum declaration is missing a semicolon after the list of constants.
The enum constants are not capitalized, which violates the Java naming convention for enums.
The switch expression is missing parentheses around the variable name.
The case labels are missing colons after the enum constants.
The default label is missing a break statement, which causes a fall-through to the next case.
The println statement is missing a closing parenthesis and a semicolon.
A possible corrected version of the code fragment is:
enum Vehicle { BICYCLE, CAR, MOTORCYCLE, TRUCK; } public class Test { public static void main(String[] args) { Vehicle v = Vehicle.BICYCLE; switch (v) { case BICYCLE: System.out.print("1"); break; case CAR: System.out.print("3"); break; case MOTORCYCLE: System.out.print("1"); break; case TRUCK: System.out.print("2"); break; default: System.out.print("0"); break; } System.out.println(); } } This would print 1 as the output. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Enum Types
The switch Statement
NEW QUESTION # 51
Which statement is true?
- A. The Lock () method returns a boolean indicator immediately regardless if it has or has not managed to acquire the lock
- B. The tryLock () method returns a boolean indicator immediately if it has managed to acquire the lock, otherwise it waits for the lock acquisition.
- C. The tryLock () method returns a boolean indicator immediately regardless if it has or has not managed to acquire the lock.
- D. The lock () method returns a boolean indicator immediately if it has managed to acquire the lock, otherwise it waits for the lock acquisition.
Answer: C
Explanation:
Explanation
The tryLock () method of the Lock interface is a non-blocking attempt to acquire a lock. It returns true if the lock is available and acquired by the current thread, and false otherwise. It does not wait for the lock to be released by another thread. This is different from the lock () method, which blocks the current thread until the lock is acquired, and does not return any value. References:
https://docs.oracle.com/en/java/javase/17/docs/api/java.base/java/util/concurrent/locks/Lock.html#tryLock(), 3, 4
NEW QUESTION # 52
......
Oracle 1Z0-829 certification exam is an excellent opportunity for developers who want to demonstrate their expertise in Java SE 17 and related technologies. Java SE 17 Developer certification exam tests the candidate's knowledge of Java language enhancements, Java libraries, Java I/O, Java concurrency, and Java security. Java SE 17 Developer certification is a valuable qualification for developers who want to advance their careers and increase their earning potential.
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