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SASInstitute Clinical Trials Programming Using SAS 9.4 Sample Questions:
1. The following SAS program is submitted:
You want to store all calculated means and standard deviations in one SAS data set.
Which statement must be added to the program?
A) ods output out=WORK.RESULTS mean=m1 m2 std=s1 s2;
B) output out=WORK.RESULTS mean=m1 m2 std=s1 s2;
C) ods output mean=m1 m2 std=s1 s2;
D) output mean std;
2. A SAS report procedure results in the log below.
What should you add to the PROC REPORT to address the blue note in this log?
A) Specify COLWIDTH= option with a value large enough to print all values in the data
B) Use DEFINE statements where FLOW is specified for each numeric variable
C) Use DEFINE statements with the WIDTH= option set large enough to print all values for each variable
D) Use a FORMAT statement with formats large enough to print all values for each numeric variable
3. Which percentage in the table is calculated incorrectly, assuming the cell counts are correct?
Percentages are rounded to the nearest whole percent.
A) 40
B) 54
C) 52
D) 44
4. Review the following procedure format:
What is the required type of data for the variable in this procedure?
A) Categorical
B) Treatment
C) Character
D) Continuous
5. The first six (6) records from the LABS data set are shown below:
The following SAS program is written to reshape this data set and place it in a new data set named LBTR.
proc transpose data=labs out=lbtr(rename = (col1 = value));
by subjid sampldat;
var Calcium Glucose Hemoglobin;
run;
Which of the following DATA steps produces a data set that is equivalent to the LBTR data set created by the PROC TRANSPOSE step above?
A) data lbtr2(drop = i calcium glucose hemoglobin);
set labs;
array orig[3] calcium glucose hemoglobin;
array testcds[3] $ 10 ("CALCIUM" "GLUCOSE" "HEMOGLOBIN");
do i = 1 to 3;
value = orig[i];
_name_ = testcds[i];
output;
end;
run;
B) data lbtr2(drop = i calcium glucose hemoglobin);
set labs;
array orig[3] calcium glucose hemoglobin;
array testcds[3] $ 10 _temporary_ ("CALCIUM" "GLUCOSE" "HEMOGLOBIN");
do i = 1 to 3;
value = orig[i];
_name_ = testcds[i];
output;
end;
run;
C) data lbtr2(drop = i calcium glucose hemoglobin);
set labs;
array orig[3] calcium glucose hemoglobin;
array testcds[3] $ 10 _temporary_ ("CALCIUM" "GLUCOSE" "HEMOGLOBIN");
do i = 1 to 3;
value = orig[i];
_name_ = testcds[i];
end;
output;
run;
D) data lbtr2(drop = i calcium glucose hemoglobin);
set labs;
array orig[3] calcium glucose hemoglobin;
array testcds[3] $ 10 ("CALCIUM" "GLUCOSE" "HEMOGLOBIN");
do i = 1 to 3;
value = orig[i];
_name_ = testcds[i];
end;
output;
run;
Solutions:
| Question # 1 Answer: B | Question # 2 Answer: D | Question # 3 Answer: D | Question # 4 Answer: D | Question # 5 Answer: B |






